GATE GUIDE

GATE CE Environmental and Transportation Formula Sheet 2027

By MD ANISH AHAMADUpdated 4 Oct 202610 min read
GATE CE Environmental and Transportation Formula Sheet 2027

This sheet collects the Environmental and Transportation Engineering formulas that GATE CE papers set again and again. Each row gives the formula, when it applies and its trap. One-line examples with made-up numbers let you test your recall.

In this guide
  1. Key takeaways
  2. How to read this sheet
  3. Environmental Engineering: water quality and treatment
  4. Environmental Engineering: air pollution and solid waste
  5. Transportation Engineering: sight distance and road curves
  6. Transportation Engineering: railways and runways
  7. Transportation Engineering: traffic flow and signals
  8. Transportation Engineering: pavement design
  9. Transportation Planning: new for 2027, with no formula pattern yet
  10. Quick revision

Key takeaways

How to read this sheet

log means base 10 and ln means natural log. In road formulas, VV is speed in km/h and vv is speed in m/s. Divide km/h by 3.6 to get m/s.

Overflow rate is flow per unit surface area of a tank. MLSS is the mixed liquor suspended solids in an aeration tank, in mg/L. Space-mean speed is the average speed over a stretch of road; time-mean speed is the average of speeds at one point. For section marks, see GATE CE subject-wise weightage for every section.

Environmental Engineering: water quality and treatment

BOD, hardness and chlorine

Formula Symbols / when it applies Watch out for
BODt=L0(1−e−kt)\text{BOD}_t = L_0(1 - e^{-kt}) L0L_0 ultimate BOD, kk base-e rate per day Base-10 form: L0(1−10−Kt)L_0(1 - 10^{-Kt}) with K=k/2.303K = k/2.303
Lt=L0e−ktL_t = L_0 e^{-kt} BOD still remaining after tt days Remaining is the complement of exerted
as CaCO3=C×50equivalent weight\displaystyle \text{as CaCO}_3 = C \times \dfrac{50}{\text{equivalent weight}} Hardness and alkalinity; equivalent weight =molecular weight/valency= \text{molecular weight}/\text{valency} Use equivalent weights, not molecular weights
Chlorine demand=dose−residual\text{Chlorine demand} = \text{dose} - \text{residual} All in mg/L The residual is a reserve, not waste

For L0=250L_0 = 250 mg/L and k=0.2k = 0.2 per day, BOD5=250(1−e−1)=158.0\text{BOD}_5 = 250(1 - e^{-1}) = 158.0 mg/L. For 48 mg/L of calcium, hardness =48×50/20=120= 48 \times 50/20 = 120 mg/L as CaCO3\text{CaCO}_3. A dose of 2.0 mg/L leaving 0.3 mg/L gives a demand of 1.7 mg/L.

Two IS 10500 values appear in the book. Total hardness is acceptable up to 200 mg/L, and permissible up to 600 mg/L where no alternative source exists. The minimum free chlorine residual at the tap is 0.2 mg/L.

Trap: A base-e constant of 0.23 per day is a base-10 constant of 0.1 per day. Read which base the question states before you write ee or 10.

Sedimentation, detention and activated sludge

Formula Symbols / when it applies Watch out for
SOR=Q/As\text{SOR} = Q/A_s AsA_s surface area of the tank Removal depends on area, not depth
vs=g(ρs−ρ)d218μ\displaystyle v_s = \dfrac{g(\rho_s - \rho)d^2}{18\mu} Stokes' law, laminar settling Square the diameter; use metres
t=V/Qt = V/Q Theoretical detention time Convert days to hours at the end
F/M=QS0VX\displaystyle F/M = \dfrac{Q S_0}{V X} S0S_0 influent BOD, XX MLSS Answer is per day
SVI=settled volume (mL/L)×1000MLSS (mg/L)\displaystyle \text{SVI} = \dfrac{\text{settled volume (mL/L)} \times 1000}{\text{MLSS (mg/L)}} Sludge settleability, mL/g Dropping the 1000 is the classic error

For Q=4800Q = 4800 m³/day on 160 m², the overflow rate is 30 m³/m²/day. A 0.05 mm particle of density 2650 kg/m³ in water with μ=10−3\mu = 10^{-3} Pa·s settles at 2.25 mm/s. A 1500 m³ tank taking 9000 m³/day holds the flow for 4 hours.

For Q=4000Q = 4000 m³/day, S0=200S_0 = 200 mg/L, V=1600V = 1600 m³ and X=2500X = 2500 mg/L, F/M=0.2F/M = 0.2 per day. A sludge settling to 240 mL/L at an MLSS of 2000 mg/L has an SVI of 120 mL/g, which is good settling.

Sewers and population forecasting

Formula Symbols / when it applies Watch out for
V=1nR2/3S1/2\displaystyle V = \frac{1}{n}R^{2/3}S^{1/2} with R=D/4R = D/4 Circular sewer running full Then check self-cleansing velocity, at least 0.6 m/s at minimum flow
Pn=P0(1+r)nP_n = P_0(1 + r)^n Geometric increase, constant percentage growth Gives the largest forecast of the three methods

A 0.4 m sewer running full has R=0.1R = 0.1 m. A town of 40,000 growing at 3 per cent a year reaches 40000×1.0310≈53,75740000 \times 1.03^{10} \approx 53{,}757 in ten years.

Environmental Engineering: air pollution and solid waste

Formula Symbols / when it applies Watch out for
H=hs+ΔhH = h_s + \Delta h Stack height plus plume rise Use HH, not hsh_s, in the plume
C=Qπuσyσzexp⁡ ⁣(−H22σz2)\displaystyle C = \dfrac{Q}{\pi u \sigma_y \sigma_z}\exp\!\left(-\dfrac{H^2}{2\sigma_z^2}\right) Ground level, on the plume centreline QQ is emission rate, uu wind speed
vs=QL×W\displaystyle v_s = \dfrac{Q}{L \times W} Gravity settling chamber Same overflow-rate logic as a tank
Stability: compare ELR with DALR =9.8= 9.8 °C/km ELR above DALR is unstable; below is stable An inversion is very stable and traps pollutants
r=ρcompacted/ρloose=Vloose/Vcompactedr = \rho_{\text{compacted}}/\rho_{\text{loose}} = V_{\text{loose}}/V_{\text{compacted}} Solid waste compaction ratio Ratio is greater than 1; 0.5 is inverted

A 40 m stack with 20 m of plume rise has H=60H = 60 m. With σz=30\sigma_z = 30 m, the exponential factor is e−2=0.135e^{-2} = 0.135. Waste compacted from 250 to 625 kg/m³ has a compaction ratio of 2.5.

Remember: Stability is a comparison, not a number. If the surrounding air cools more slowly than 9.8 °C per km, a rising parcel sinks back and the air is stable.

This sheet is a selection. The book's last-minute sheet of formulae and code constants covers all eight technical sections, with each value traced to a worked solution. It is part of the GATE CE 2027 book.

Transportation Engineering: sight distance and road curves

Sight distances and horizontal curves

Formula Symbols / when it applies Watch out for
SSD=vt+v22gf\displaystyle \text{SSD} = vt + \dfrac{v^2}{2gf} vv in m/s, tt reaction time, ff friction Convert km/h to m/s first
OSD=d1+d2+d3\text{OSD} = d_1 + d_2 + d_3 d1=vbtd_1 = v_b t, d2=vbT+2sd_2 = v_b T + 2s, d3=vTd_3 = vT Drop d3d_3 on a one-way road
s=0.7vb+6s = 0.7v_b + 6, T=4s/aT = \sqrt{4s/a} vbv_b overtaken vehicle speed, aa acceleration Use vbv_b, not the design speed, in d1d_1 and d2d_2
e+f=V2127R\displaystyle e + f = \dfrac{V^2}{127R} VV in km/h, RR in m IRC caps ee at 0.07 in plain terrain; ff at 0.15
Ls=0.0215V3CR\displaystyle L_s = \dfrac{0.0215V^3}{CR}, C=8075+V\displaystyle C = \dfrac{80}{75 + V} Transition length, rate of change of centrifugal acceleration VV in km/h, not m/s

At 72 km/h (v=20v = 20 m/s), with t=2.5t = 2.5 s and f=0.35f = 0.35, the SSD is 50+58.25=108.2550 + 58.25 = 108.25 m. At V=60V = 60 km/h and R=200R = 200 m, e+f=0.142e + f = 0.142. With e=0.07e = 0.07, the friction needed is 0.072, inside the limit. There, C=0.593C = 0.593 and Ls=39.18L_s = 39.18 m.

Summit and valley curves

Formula Symbols / when it applies Watch out for
L=NS2(2h1+2h2)2\displaystyle L = \dfrac{NS^2}{\left(\sqrt{2h_1} + \sqrt{2h_2}\right)^2} Summit, L>SL > S; NN deviation angle Constant 4.4 for SSD (h1=1.2h_1 = 1.2 m, h2=0.15h_2 = 0.15 m); 9.6 for OSD
L=NS22(h1+Stan⁡α)\displaystyle L = \dfrac{NS^2}{2(h_1 + S\tan\alpha)} Valley, headlight sight distance, L>SL > S Not the summit formula; check comfort too

For N=0.06N = 0.06 and an SSD of 120 m, a summit curve needs L=0.06×1202/4.4=196.4L = 0.06 \times 120^2/4.4 = 196.4 m. For a valley with N=0.06N = 0.06, S=100S = 100 m, h1=0.75h_1 = 0.75 m and α=1∘\alpha = 1^\circ, L=120.2L = 120.2 m.

In one line: Summit curves are designed on sight distance alone; valley curves take the greater of headlight distance and comfort.

Transportation Engineering: railways and runways

Formula Symbols / when it applies Watch out for
e=GV2127R\displaystyle e = \dfrac{GV^2}{127R} Equilibrium cant; GG gauge in m, VV in km/h Broad gauge maximum cant is 165 mm
Elevation correction: +7+7 per cent per 300 m Above mean sea level, on the basic runway length Apply temperature correction to the elevation-corrected length

On broad gauge (G=1.676G = 1.676 m) at 60 km/h and R=400R = 400 m, e=0.1188e = 0.1188 m, or 118.8 mm. A 1800 m basic runway at 600 m elevation becomes 1800+1800×0.07×2=20521800 + 1800 \times 0.07 \times 2 = 2052 m.

Transportation Engineering: traffic flow and signals

Formula Symbols / when it applies Watch out for
q=kvsq = k v_s Flow, density, space-mean speed Not the time-mean speed
vs=n∑1/vi\displaystyle v_s = \dfrac{n}{\sum 1/v_i}; vt=∑vin\displaystyle v_t = \dfrac{\sum v_i}{n} Harmonic and arithmetic means of spot speeds vs≤vtv_s \le v_t always
v=vf(1−k/kj)v = v_f(1 - k/k_j), qmax⁡=vfkj4\displaystyle q_{\max} = \dfrac{v_f k_j}{4} Greenshields linear model Capacity at kj/2k_j/2 and vf/2v_f/2
PHF=hourly volume4×peak 15-min volume\displaystyle \text{PHF} = \dfrac{\text{hourly volume}}{4 \times \text{peak 15-min volume}} Uniformity of the peak hour Never above 1.0
C0=1.5L+51−Y\displaystyle C_0 = \dfrac{1.5L + 5}{1 - Y} Webster; LL lost time per cycle, YY sum of critical flow ratios YY near 1 makes the cycle explode
c=s×g/Cc = s \times g/C Approach capacity; ss saturation flow Saturation flow alone is not capacity

For spot speeds of 30 and 60 km/h, vt=45v_t = 45 km/h but vs=40v_s = 40 km/h. With vf=90v_f = 90 km/h and kj=120k_j = 120 veh/km, qmax⁡=2700q_{\max} = 2700 veh/h. An hour of 2400 vehicles peaking at 720 in 15 minutes gives a PHF of 0.833. Webster with L=10L = 10 s and Y=0.6Y = 0.6 gives a 50 s cycle.

Trap: At a signal, 1800 veh/h is a rate during green. With 30 s of green in a 90 s cycle, the approach carries 600 veh/h.

Transportation Engineering: pavement design

Formula Symbols / when it applies Watch out for
N=365×A×D×F×[(1+r)n−1]r\displaystyle N = \dfrac{365 \times A \times D \times F \times [(1 + r)^n - 1]}{r} IRC:37 design traffic, million standard axles; AA commercial vehicles/day, DD lane distribution, FF VDF Divide by 10610^6 for msa
damage∝(axle loadstandard axle)4\displaystyle \text{damage} \propto \left(\dfrac{\text{axle load}}{\text{standard axle}}\right)^4 Fourth-power law; standard axle 80 kN Twice the load does sixteen times the damage
l=[Eh312(1−μ2)k]1/4\displaystyle l = \left[\dfrac{Eh^3}{12(1 - \mu^2)k}\right]^{1/4} Westergaard radius of relative stiffness, IRC:58 rigid pavements Fourth root, so ll grows as h3/4h^{3/4}
CBR=test loadstandard load×100\displaystyle \text{CBR} = \dfrac{\text{test load}}{\text{standard load}} \times 100 Standard load 1370 kg at 2.5 mm Take the 2.5 mm value unless 5 mm is higher

With A=2000A = 2000, D=0.75D = 0.75, F=3F = 3, r=0.05r = 0.05 and n=10n = 10 years, the growth series is 12.578 and N=20.66N = 20.66 msa. An axle 1.5 times the standard does 1.54=5.061.5^4 = 5.06 times the damage. For E=3×105E = 3 \times 10^5 kg/cm², h=25h = 25 cm, μ=0.15\mu = 0.15 and k=6k = 6 kg/cm³, l=90.34l = 90.34 cm. A load of 68.5 kg at 2.5 mm gives a CBR of 5 per cent.

Transportation Planning: new for 2027, with no formula pattern yet

The 2027 syllabus adds four-step travel demand modelling. The steps run in order: trip generation, trip distribution, mode choice and traffic assignment. Each answers one question: how many trips, where to, by what mode, and by which route.

It has drawn zero marks in all 1,040 counted questions from the sixteen papers of 2019 to 2026. There is no pattern to learn from, so read the four steps once. The GATE CE 2027 syllabus changes guide lists every addition in both sections.

More formula sheets: all of GATE Civil · Fluid Mechanics and Hydrology · Geotechnical · Structural Engineering

Quick revision

  1. BOD exerted is L0(1−e−kt)L_0(1 - e^{-kt}); switch to base 10 only with K=k/2.303K = k/2.303.
  2. Convert hardness with equivalent weights; IS 10500 total hardness is 200 mg/L acceptable, 600 permissible.
  3. Overflow rate is Q/AsQ/A_s, F/M is QS0/(VX)QS_0/(VX) per day, and SVI needs the factor of 1000.
  4. Use the effective stack height hs+Δhh_s + \Delta h in the plume, and compare ELR with 9.8 °C/km for stability.
  5. SSD needs speed in m/s; e+f=V2/(127R)e + f = V^2/(127R) needs km/h, with ee capped at 0.07.
  6. Summit curves use 4.4 for SSD and 9.6 for OSD; broad gauge cant stops at 165 mm.
  7. q=kvq = kv takes the space-mean speed; Greenshields capacity is vfkj/4v_f k_j/4; Webster is (1.5L+5)/(1−Y)(1.5L + 5)/(1 - Y).
  8. Check your calculator steps against the virtual calculator guide, and fit this sheet into the last two months plan.

Frequently asked questions

Is the BOD rate constant in base e or base 10?

Both conventions exist, so read the question. In base e the BOD exerted is L0(1−e−kt)L_0(1 - e^{-kt}). In base 10 it is L0(1−10−Kt)L_0(1 - 10^{-Kt}), with K=k/2.303K = k/2.303. A base-e constant of 0.23 per day equals a base-10 constant of 0.1 per day. Using 0.23 in the base-10 form inflates the answer, and that inflated value is the standard wrong option.

Why does the relation q=kvq = kv need the space-mean speed?

Flow equals density times speed only when the speed is averaged over a length of road, which is the space-mean speed. Space-mean speed is the harmonic mean of spot speeds and is never larger than the time-mean speed, which is the arithmetic mean. Using the time-mean speed in q=kvq = kv overestimates the flow.

Should I use 4.4 or 9.6 in the summit curve formula?

Use 4.4 when the curve is designed for stopping sight distance, with an eye height of 1.2 m and an object height of 0.15 m. Use 9.6 for overtaking sight distance, where both heights are 1.2 m. Both constants belong to the case where the curve is longer than the sight distance, so check that L>SL > S after you compute.

Is Transportation Planning examined in GATE CE?

It is new in the 2027 syllabus as four-step travel demand modelling: trip generation, trip distribution, mode choice and traffic assignment. It drew zero marks in all 1,040 counted questions from 2019 to 2026, so it is untested in the counted record. There is no past pattern to learn from, so read the four steps once and know what each one answers.

Can I take a formula sheet into the GATE CE exam?

No paper of your own is normally allowed in the hall. The exam gives you a virtual calculator and a scribble pad. Many candidates write a few easily forgotten constants, such as 4.4, 9.6 and 0.0215, on the pad in the first minutes. The rules can change by year, so confirm the current rules at gate2027.iitm.ac.in.

Sources

Dates, fees and the syllabus are set by the GATE 2027 organising institute and can change. Always confirm at gate2027.iitm.ac.in.

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