GATE GUIDE

GATE ECE Formula Sheet 2027: Key Formulas by Subject

By MD ANISH AHAMADUpdated 4 Oct 20268 min read
GATE ECE Formula Sheet 2027: Key Formulas by Subject

This GATE ECE formula sheet collects the formulas that the five counted GATE EC papers (2010, 2019, 2020, 2025 and 2026) used most, grouped by syllabus section, with the trap beside each one. It is a free selection from the last-minute revision sheet of the GATE ECE 2027 book. Use it to test your recall, then practise each formula on past questions.

In this guide
  1. Key takeaways
  2. How to read this sheet
  3. Networks, Signals and Systems
  4. Engineering Mathematics
  5. Analog Circuits
  6. Communications
  7. Digital Circuits
  8. Electronic Devices
  9. Control Systems
  10. Electromagnetics
  11. General Aptitude
  12. Subject-wise formula sheets
  13. Quick revision

Key takeaways

How to read this sheet

Some terms first. A phasor is the complex amplitude of a sinusoid at one frequency. The region of convergence (ROC) is the set of zz for which a z-transform sum converges. A trap is the specific slip that a wrong option is built to catch.

Notation: ω=2πf\omega = 2\pi f; VmV_m is a peak value and Vrms=Vm/2V_{\text{rms}} = V_m/\sqrt{2}; log⁡\log is base 10, ln⁡\ln natural, and log⁡2\log_2 wherever the unit is bits. VT=kT/q≈26 mVV_T = kT/q \approx 26\text{ mV} at 300 K. Op-amps and sources are ideal unless a question says otherwise.

Networks, Signals and Systems

The largest section, at a mean of 17.0 marks across the counted papers.

Formula Watch out for
ZL=jωLZ_L = j\omega L, ZC=1jωC\displaystyle Z_C = \dfrac{1}{j\omega C}; Pavg=VrmsIrmscos⁡θP_{\text{avg}} = V_{\text{rms}} I_{\text{rms}} \cos\theta, θ=∠Z\theta = \angle Z A 50 Hz source is ω=314\omega = 314 rad/s; meters read rms, v(t)=Vmcos⁡ωtv(t) = V_m \cos\omega t is peak
Reciprocal: z12=z21z_{12} = z_{21}, y12=y21y_{12} = y_{21}, AD−BC=1AD - BC = 1, h12=−h21h_{12} = -h_{21}; symmetric: z11=z22z_{11} = z_{22}, A=DA = D Only the h-parameter condition carries a minus sign
RthR_{\text{th}}: independent VV short, II open; with dependent sources use a test source Dependent sources are never deactivated; superposition never applies to power
x(t)=x(∞)+[x(0+)−x(∞)]e−t/τx(t) = x(\infty) + \big[x(0^+) - x(\infty)\big]e^{-t/\tau}, τ=RC\tau = RC or L/RL/R vCv_C and iLi_L jump if switching makes a capacitor loop or inductor cut-set
ω0=1LC\displaystyle \omega_0 = \dfrac{1}{\sqrt{LC}}, BW=ω0/Q\text{BW} = \omega_0/Q; series Q=ω0L/RQ = \omega_0 L/R, parallel Q=R/(ω0L)Q = R/(\omega_0 L) Parallel QQ is the reciprocal form
Right-sided: ROC ∣z∣>∣p∣max⁡\vert z \vert > \vert p \vert_{\max}; causal and stable iff all poles inside ∣z∣=1\vert z \vert = 1 The ROC never contains a pole; stable iff ROC contains the unit circle
fs>2fmax⁡f_s > 2f_{\max}; alias at ∣f−kfs∣\vert f - kf_s \vert Nyquist rate is 2fmax⁡2f_{\max}, Nyquist frequency is fs/2f_s/2
lim⁡t→∞f(t)=lim⁡s→0sF(s)\lim_{t\to\infty} f(t) = \lim_{s\to 0} sF(s) Valid only if every pole of sF(s)sF(s) is in the open left half-plane
Lengths NN and MM convolve to N+M−1N + M - 1 Linear and circular convolution differ
E=∫∣x∣2dt=12π∫∣X(jω)∣2dω\displaystyle E = \int \vert x \vert^2 dt = \dfrac{1}{2\pi}\int \vert X(j\omega) \vert^2 d\omega The 1/2π1/2\pi is present in ω\omega and absent in ff

Fourier series symmetry: even symmetry removes sine terms (bn=0b_n = 0), odd symmetry removes cosine terms and a0a_0, and half-wave symmetry, x(t)=−x(t±T/2)x(t) = -x(t \pm T/2), removes the even harmonics. A system is LTI only if every block in a cascade or parallel connection is.

FIR and IIR filter design is newly named in the 2027 syllabus, though 2019 Q39 and Q54 were already filter-design questions. The GATE ECE 2027 syllabus changes guide sets out all four changes.

Trap: Half-wave symmetry removes harmonics; even and odd symmetry remove terms. Swapping those two rules lands on a printed distractor.

Engineering Mathematics

Formula Watch out for
Polar dA=r dr dθdA = r\,dr\,d\theta; spherical dV=ρ2sin⁡ϕ dρ dϕ dθdV = \rho^2 \sin\phi\,d\rho\,d\phi\,d\theta The dropped rr is this section's most expensive slip
Ax=bAx = b consistent iff rank(A)=rank([A∣b])\text{rank}(A) = \text{rank}([A \mid b]); unique iff that rank =n= n det⁡A=0\det A = 0 means no solution or infinitely many; read which is asked
∮Cf dz=2πj∑Res\oint_C f\,dz = 2\pi j \sum \text{Res}; simple pole: lim⁡z→z0(z−z0)f(z)\lim_{z \to z_0}(z - z_0)f(z) Count only poles strictly inside; clockwise flips the sign
∑λi=trace\sum \lambda_i = \text{trace}, ∏λi=det⁡A\prod \lambda_i = \det A A triangular matrix shows its eigenvalues on the diagonal
Roots m1≠m2m_1 \ne m_2: C1em1x+C2em2xC_1 e^{m_1 x} + C_2 e^{m_2 x}; repeated: (C1+C2x)emx(C_1 + C_2 x)e^{mx}; α±jβ\alpha \pm j\beta: eαx(C1cos⁡βx+C2sin⁡βx)e^{\alpha x}(C_1 \cos\beta x + C_2 \sin\beta x) The repeated root needs the factor xx
E[aX+bY]=aE[X]+bE[Y]E[aX + bY] = aE[X] + bE[Y]; Var(X+Y)=Var X+Var Y\text{Var}(X + Y) = \text{Var}\,X + \text{Var}\,Y if uncorrelated E[X2]≠(E[X])2E[X^2] \ne (E[X])^2; the gap is the variance
ρ=Cov(X,Y)σXσY\displaystyle \rho = \dfrac{\text{Cov}(X, Y)}{\sigma_X \sigma_Y}; byx=n∑xy−∑x∑yn∑x2−(∑x)2\displaystyle b_{yx} = \dfrac{n\sum xy - \sum x \sum y}{n\sum x^2 - (\sum x)^2}, a=yˉ−byxxˉa = \bar{y} - b_{yx}\bar{x} The line of yy on xx differs from xx on yy; r2=byx bxyr^2 = b_{yx}\,b_{xy}

Correlation and regression analysis is new in the 2027 syllabus. 2026 Q38 already asked correlation; regression has no counted precedent.

Analog Circuits

Formula Watch out for
Half-wave: Vavg=Vm/πV_{\text{avg}} = V_m/\pi, Vrms=Vm/2V_{\text{rms}} = V_m/2; full-wave: 2Vm/π2V_m/\pi, Vm/2V_m/\sqrt{2} VmV_m is the peak after the stated diode drops
Inverting −Rf/R1-R_f/R_1; non-inverting 1+Rf/R11 + R_f/R_1 Virtual short needs negative feedback; not in a Schmitt trigger
gm=IC/VTg_m = I_C/V_T, rπ=β/gmr_\pi = \beta/g_m, Av=−gmRCA_v = -g_m R_C Unbypassed RER_E: Av=−gmRC1+gmRE\displaystyle A_v = \dfrac{-g_m R_C}{1 + g_m R_E}, Rin=rπ+(β+1)RER_{\text{in}} = r_\pi + (\beta + 1)R_E
MOSFET gm=2IDVov=2μCox(W/L)ID\displaystyle g_m = \dfrac{2I_D}{V_{ov}} = \sqrt{2\mu C_{ox}(W/L)I_D} gm∝IDg_m \propto \sqrt{I_D} for a MOSFET, ∝IC\propto I_C for a BJT
Rs=Vin,min−VzIz,min⁡+IL,max⁡\displaystyle R_s = \dfrac{V_{\text{in,min}} - V_z}{I_{z,\min} + I_{L,\max}} Check Zener power at the opposite corner
Ad=gmRCA_d = g_m R_C differential out, gmRC/2g_m R_C/2 single-ended; CMRR=∣Ad/Acm∣\text{CMRR} = \vert A_d / A_{cm} \vert The factor of 2 on single-ended output
fc=12πRC\displaystyle f_c = \dfrac{1}{2\pi RC} Hz, ωc=1RC\displaystyle \omega_c = \dfrac{1}{RC} rad/s The answer unit decides the 2π2\pi

Remember: Removing the emitter bypass capacitor lowers the gain and raises the input resistance. Both directions, or the mark is gone.

This page is a selection. The book's last-minute sheet lists every ranked concept section by section, with the counted question numbers behind each formula, a trap on every entry and the MCQ guessing arithmetic. It is part of the GATE ECE 2027 book, with 925 questions with worked solutions and 10 full mock tests.

Communications

Formula Watch out for
Antipodal (BPSK, QPSK): Pb=Q(2Eb/N0)P_b = Q\big(\sqrt{2E_b/N_0}\big); orthogonal: Q(Eb/N0)Q\big(\sqrt{E_b/N_0}\big) N0/2N_0/2 is the two-sided PSD; MAP equals ML only with equal priors
FM β=Δf/fm\beta = \Delta f / f_m; Carson BW=2(Δf+fm)\text{BW} = 2(\Delta f + f_m); power Ac2/2A_c^2/2 kfk_f in Hz/V or rad/s/V differs by 2π2\pi
μ=Vmax⁡−Vmin⁡Vmax⁡+Vmin⁡\displaystyle \mu = \dfrac{V_{\max} - V_{\min}}{V_{\max} + V_{\min}}; Pt=Pc(1+μ2/2)P_t = P_c(1 + \mu^2/2); η=μ22+μ2\displaystyle \eta = \dfrac{\mu^2}{2 + \mu^2} Maximum efficiency is 1/31/3 at μ=1\mu = 1
Sy(f)=∣H(f)∣2Sx(f)S_y(f) = \vert H(f) \vert^2 S_x(f) ∣H∣2\vert H \vert^2, not HH
H=−∑pilog⁡2piH = -\sum p_i \log_2 p_i; C=Blog⁡2(1+SNR)C = B\log_2(1 + \text{SNR}); BSC C=1−H(p)C = 1 - H(p) Use base 2 for bits
Hamming: 2n−k≥n+12^{n-k} \ge n + 1, dmin⁡=3d_{\min} = 3; corrects tt if dmin⁡≥2t+1d_{\min} \ge 2t + 1 Two errors decode to the wrong codeword
Rb=nfsR_b = n f_s; SQNR=6.02n+1.76\text{SQNR} = 6.02n + 1.76 dB Symbol rate times log⁡2M\log_2 M is bit rate

Digital Circuits

Formula Watch out for
Mod-NN counter: ⌈log⁡2N⌉\lceil \log_2 N \rceil flip-flops; nn toggle stages divide by 2n2^n Ring counter nn states, Johnson 2n2n
Maximal LFSR length 2n−12^n - 1 XOR feedback never enters all zeros
A 2n2^n-to-1 mux realises any function of n+1n + 1 variables A 4-to-1 mux does any three-variable function
Two's complement: −2n−1-2^{n-1} to 2n−1−12^{n-1} - 1 Overflow is two same-sign operands giving the opposite sign
Tmin⁡=tcq+tcomb,max+tsuT_{\min} = t_{cq} + t_{\text{comb,max}} + t_{su}; hold: tcq+tcomb,min≥tholdt_{cq} + t_{\text{comb,min}} \ge t_{\text{hold}} Slowing the clock never fixes hold
DAC Vout=Vref⋅D/2nV_{\text{out}} = V_{\text{ref}} \cdot D/2^n Full scale is Vref(2n−1)/2nV_{\text{ref}}(2^n - 1)/2^n

Electronic Devices

Formula Watch out for
I=IS(eV/ηVT−1)I = I_S\big(e^{V/\eta V_T} - 1\big) One decade of current costs about 60 mV at η=1\eta = 1
D/μ=kT/qD/\mu = kT/q; σ=q(nμn+pμp)\sigma = q(n\mu_n + p\mu_p) cm²/s against m²/s is a factor 10410^4
Vbi=kTqln⁡NANDni2\displaystyle V_{bi} = \dfrac{kT}{q}\ln\dfrac{N_A N_D}{n_i^2} Natural logarithm
ID=12μCoxWL(VGS−Vth)2\displaystyle I_D = \tfrac{1}{2}\mu C_{ox}\dfrac{W}{L}(V_{GS} - V_{th})^2, for VDS≥VGS−VthV_{DS} \ge V_{GS} - V_{th} Check whether the given kk already holds the 12\displaystyle \tfrac{1}{2}
Threshold at surface potential 2ϕF2\phi_F, ϕF=VTln⁡(NA/ni)\phi_F = V_T \ln(N_A/n_i) 2ϕF2\phi_F, not ϕF\phi_F
λ(μm)=1.24/Eg(eV)\lambda(\mu\text{m}) = 1.24/E_g(\text{eV}); α=β/(1+β)\alpha = \beta/(1 + \beta) Zener has a negative temperature coefficient, avalanche positive

Scaling in MOSFETs is new for 2027. Under constant-field scaling by κ\kappa, delay falls by κ\kappa, power by κ2\kappa^2, and power density stays constant.

Control Systems

Formula Watch out for
G(s)=C(sI−A)−1B+DG(s) = C(sI - A)^{-1}B + D; poles are eigenvalues of AA A cancellation can hide an unstable state
Closed loop G1+GH\displaystyle \dfrac{G}{1 + GH} (negative feedback) Positive feedback gives 1−GH1 - GH
Routh: sign changes in column one == right-half-plane poles A row of zeros: differentiate the auxiliary polynomial from the row above
Overshoot fraction Mp=e−πζ/1−ζ2M_p = e^{-\pi\zeta/\sqrt{1 - \zeta^2}}; ts≈4ζωn\displaystyle t_s \approx \dfrac{4}{\zeta\omega_n} (2 per cent) Use 3/(ζωn)3/(\zeta\omega_n) only when 5 per cent is stated
Step e=11+Kp\displaystyle e = \dfrac{1}{1 + K_p}; ramp 1/Kv1/K_v; parabola 1/Ka1/K_a Unity feedback only; the "1 +" is for the step
Asymptotes (2k+1)180∘n−m\displaystyle \dfrac{(2k + 1)180^\circ}{n - m}, centroid ∑p−∑zn−m\displaystyle \dfrac{\sum p - \sum z}{n - m} Real-axis locus: odd count to the right
PID: Kp+Ki/s+KdsK_p + K_i/s + K_d s The integral term raises the system type by one

Gain margin is read at the phase crossover and phase margin at the gain crossover. Swapping them is a reachable wrong answer.

Electromagnetics

Formula Watch out for
η0=120π≈377 Ω\eta_0 = 120\pi \approx 377\ \Omega; Γ=η2−η1η2+η1\displaystyle \Gamma = \dfrac{\eta_2 - \eta_1}{\eta_2 + \eta_1}, τ=1+Γ\tau = 1 + \Gamma Power fractions are ∣Γ∣2\vert \Gamma \vert^2 and 1−∣Γ∣21 - \vert \Gamma \vert^2; τ\tau can exceed 1
Pavg=∣E0∣22η\displaystyle P_{\text{avg}} = \dfrac{\vert E_0 \vert^2}{2\eta} for peak E0E_0 No 12\displaystyle \tfrac{1}{2} for rms
Zin=Z0ZL+jZ0tan⁡βlZ0+jZLtan⁡βl\displaystyle Z_{\text{in}} = Z_0 \dfrac{Z_L + jZ_0 \tan\beta l}{Z_0 + jZ_L \tan\beta l}; quarter-wave Z02/ZLZ_0^2/Z_L β\beta uses the line wavelength λ0/εr\lambda_0/\sqrt{\varepsilon_r}
VSWR=1+∣Γ∣1−∣Γ∣\displaystyle \text{VSWR} = \dfrac{1 + \vert \Gamma \vert}{1 - \vert \Gamma \vert} One Smith chart turn is λ/2\lambda/2
fc=c2(m/a)2+(n/b)2\displaystyle f_c = \dfrac{c}{2}\sqrt{(m/a)^2 + (n/b)^2}; TE10\text{TE}_{10} at c/2ac/2a No TM10\text{TM}_{10} mode
Friis PrPt=GtGr(λ4πR)2\displaystyle \dfrac{P_r}{P_t} = G_t G_r \left(\dfrac{\lambda}{4\pi R}\right)^2 Gains as ratios, not dB
δ=2/(ωμσ)\delta = \sqrt{2/(\omega\mu\sigma)} Syllabus-named; no counted question computes it

For how much each section is worth, see the GATE ECE subject-wise weightage, and for the concepts behind these formulas, the GATE ECE important topics.

General Aptitude

The full method for these 15 marks is in how to prepare for GATE General Aptitude.

In one line: A blind four-way MCQ guess has expected value exactly zero, so eliminate one option before you guess.

Subject-wise formula sheets

Each of these goes deeper on one part of the GATE ECE paper, with a worked example and the trap for every formula:

Quick revision

  1. Reciprocity is h12=−h21h_{12} = -h_{21} for h-parameters; every other set has no minus sign.
  2. A stable, causal discrete system has every pole strictly inside the unit circle.
  3. Antipodal is Q(2Eb/N0)Q(\sqrt{2E_b/N_0}); orthogonal drops the 2.
  4. FM power is Ac2/2A_c^2/2 whatever the modulation index.
  5. Johnson counters have 2n2n states; ring counters have nn.
  6. gmg_m grows with ICI_C for a BJT and with ID\sqrt{I_D} for a MOSFET.
  7. Gain margin at the phase crossover, phase margin at the gain crossover.
  8. Write units beside every number, and round only the final answer.

Frequently asked questions

Can I take a formula sheet into the GATE ECE exam?

No. You cannot carry paper, notes or a physical calculator into the exam hall. The exam provides a virtual calculator and rough sheets. A useful habit is to write the few formulas you forget under pressure on the rough sheet in the first five minutes. Confirm the current exam-day rules at gate2027.iitm.ac.in.

Which GATE ECE formulas are asked most often?

In the five GATE EC papers the book counts, 2010, 2019, 2020, 2025 and 2026, phasor analysis, the z-transform region of convergence, the two-port reciprocity conditions, detection error probability and angle modulation appeared in all five. Learn those formulas together with their traps first.

What is the difference between BPSK and orthogonal signalling error probability?

Antipodal signalling such as BPSK has bit error probability Q(2Eb/N0)Q(\sqrt{2E_b/N_0}), while orthogonal signalling has Q(Eb/N0)Q(\sqrt{E_b/N_0}). The factor of 2 inside the square root is the whole difference, and it is a common distractor. Also keep N0/2N_0/2 as the two-sided noise density and N0N_0 as the one-sided one.

Is the reciprocity condition for h-parameters the same as for z-parameters?

No. A reciprocal two-port has z12=z21z_{12} = z_{21}, y12=y21y_{12} = y_{21} and AD−BC=1AD - BC = 1, but for h-parameters the condition is h12=−h21h_{12} = -h_{21}. The minus sign is the trap. A symmetric network adds z11=z22z_{11} = z_{22}, y11=y22y_{11} = y_{22} or A=DA = D.

How should I revise formulas before GATE ECE?

Read a compact formula sheet once a day in the last two weeks and once more on the exam morning. For each formula, know when it applies and the trap built around it. Write the unit beside every number, keep rad/s and Hz apart, carry full precision and round only the final numerical answer.

Sources

Dates, fees and the syllabus are set by the GATE 2027 organising institute and can change. Always confirm at gate2027.iitm.ac.in.

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